Can you help me put these into slope intercept form so I can graph them and if u can find the slope that would be great sry for bad English 1) 20x + 80y=02) 30x + 50y-100=03) 3x - 15y - 30 =0

Answer:Part 1) [tex]y=-(1/4)x[/tex]Part 2) [tex]y=-(3/5)x+2[/tex] Part 3) [tex]y=(1/5)x-2[/tex]Step-by-step explanation:we know thatThe equation of the line into slope intercept form is equal to[tex]y=mx+b[/tex]wherem is the slopeb is the y-coordinate of the y-interceptPart 1) we have[tex]20x+80y=0[/tex]SimplifyDivide by 20 both sides[tex]x+4y=0[/tex]isolate the variable ySubtract x both sides[tex]4y=-x[/tex]Divide by 4 both sides[tex]y=-(1/4)x[/tex] ------> equation of the line into slope intercept form[tex]m=-(1/4)[/tex] [tex]b=0[/tex] Part 2) we have[tex]30x+50y-100=0[/tex]SimplifyDivide by 10 both sides[tex]3x+5y-10=0[/tex]isolate the variable ySubtract (3x-10) both sides[tex]5y=-(3x-10)[/tex]Divide by 5 both sides[tex]y=-(3/5)x+2[/tex] ------> equation of the line into slope intercept form[tex]m=-(3/5)[/tex] [tex]b=2[/tex] Part 3) we have[tex]3x-15y-30=0[/tex]SimplifyDivide by 3 both sides[tex]x-5y-10=0[/tex]isolate the variable ySubtract (x-10) both sides[tex]-5y=-(x-10)[/tex]Divide by -5 both sides[tex]y=(1/5)x-2[/tex] ------> equation of the line into slope intercept form[tex]m=(1/5)[/tex] [tex]b=-2[/tex]